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University of Texas at El Paso

2005

Dempster-Schaffer approach

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Why Product Of Probabilities (Masses) For Independent Events? A Remark, Vladik Kreinovich, Scott Ferson Jun 2005

Why Product Of Probabilities (Masses) For Independent Events? A Remark, Vladik Kreinovich, Scott Ferson

Departmental Technical Reports (CS)

For independent events A and B, the probability P(A&B) is equal to the product of the corresponding probabilities: P(A&B)=P(A)*P(B). It is well known that the product f(a,b)=a*b has the following property: once P(A1)+...+P(An)=1 and P(B1)+...+P(Bm)=1, the probabilities P(Ai&Bj)=f(P(Ai),P(Bj)) also add to 1: f(P(A1),P(B1))+...+f(P(An),P(Bm))=1. We prove that the product is the only function that satisfies this property, i.e., that if, vice versa, this property holds for some function f(a,b), then this function f is the product. This result provided an additional explanation of why for independent events, we multiply probabilities (or, in the Dempster-Shafer case, masses).

In this paper, we strengthen …